DISCOVERY SCIENCE CENTER
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Home Physics Lessons Form 4 Form 5 Today's Physics Lesson - Form 4 Boyle's Law Q1
• Figure shows a glass capillary tube, closed at one end, with a drop of mercury trapped inside. When the tube is in the horizontal position, the length of the air column in the glass tube is 8 cm. The length of the mercury thread is 2 cm. What is • (a) the pressure of the column of trapped air when the glass tube is held horizontally? • (b) the length of the column of trapped air when the glass tube is held vertically with its open end at the top? [Atmospheric pressure = 76 cm Hg] Charles' Law Q2 • A balloon is filled with 150 cm3 of gas at 35 °C. The balloon is immersed in a beaker of water and the water is heated so that the pressure in the balloon remains constant. What is the volume of the gas when its temperature reaches 50 °C? Q3 • A constant pressure of 100 kPa is applied to a volume of air in a cylinder. The initial height of the piston is 20 cm from the base of the cylinder. What is the final height of the piston if the temperature of this system is increased from an initial temperature of 300 K to a final temperature of 400 K?
Q4 (27 sep 2010)
• Diagram (a) shows a column of air trapped in a narrow capillary tube held vertically. The atmospheric pressure at room temperature is P cm Hg. • (a) State the pressure of the air trapped in the capillary tube, in terms of P .cm Hg as shown in diagram (a). • (b) What will be observed if the capillary tube is held in a horizontal position as shown in Diagram (b)? • (c) If l1 = 10 cm, l2 = 11 cm and P = 76 cm Hg, what is the pressure of the trapped air when the tube is held vertically? • (d) State two assumptions you made in the calculations in (c).
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